Z=(1+i)(2i+3)/1-i+i^6+(2-i)^3

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Solution for Z=(1+i)(2i+3)/1-i+i^6+(2-i)^3 equation: 


x in (-oo:+oo)

Z = ((i+1)*(2*i+3))/1+(2-i)^3+i^6-i // - ((i+1)*(2*i+3))/1+(2-i)^3+i^6-i

Z-(((i+1)*(2*i+3))/1)-(2-i)^3-i^6+i = 0

Z-((i+1)*(2*i+3))-(2-i)^3-i^6+i = 0

Z-1*(i+1)*(2*i+3)-1*(2-i)^3-i^6+i = 0

Z-1*(i+1)*(2*i+3)-1*(2-i)^3-i^6+i = 0

Z-i^6+i^3-8*i^2+7*i+i-11 = 0

Z-i^6+i^3-8*i^2+8*i-11 = 0

Z-i^6+i^3-8*i^2+8*i-11 = 0

x belongs to the empty set

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